What is the exact ratio of the total number of -bonds to -bonds present in one molecule of benzene ( — Hydrocarbons Chemistry Question
Question
What is the exact ratio of the total number of $\pi$ -bonds to $\sigma$ -bonds present in one molecule of benzene ($C_6H_6$)?
Answer: A
💡 Solution & Explanation
The structure of benzene consists of a hexagonal ring of 6 carbon atoms, with one hydrogen attached to each. There are 6 $C-C$ $\sigma$ -bonds forming the ring and 6 $C-H$ $\sigma$ -bonds, giving a total of 12 $\sigma$ -bonds. The completely delocalized $\pi$ system is equivalent to 3 $\pi$ -bonds. The ratio of $\pi$ -bonds to $\sigma$ -bonds is $3:12$, which simplifies to $1:4$.
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