Regarding the effect of hybridized carbon atoms, the correct decreasing order of electron-withdrawin — GOC and Organic Chemistry Basics Chemistry Question
Question
Regarding the $-I$ effect of hybridized carbon atoms, the correct decreasing order of electron-withdrawing power is:
Answer: A
💡 Solution & Explanation
Electronegativity of a carbon atom increases with its percentage of s-character. $sp$ hybridized carbons (50% s) are more electronegative and exert a stronger $-I$ effect than $sp^2$ carbons (33.3% s), which in turn are stronger than $sp^3$ carbons (25% s).
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