Calculate the sum of the degree of unsaturation (DBE) and the total number of (primary) hydrogen ato — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

Isopentane (2-methylbutane) has the structure $CH_3-CH(CH_3)-CH_2-CH_3$. Since it is a saturated acyclic alkane, its DBE is 0. It contains three terminal methyl groups, each bearing 3 primary hydrogens. Total $1^\circ$ hydrogens = $3 \times 3 = 9$. Sum = 0 + 9 = 9.