What is the calculated Effective Atomic Number (EAN) of the vanadium atom in the stable hexacarbonyl — Coordination Compounds Chemistry Question
Question
What is the calculated Effective Atomic Number (EAN) of the vanadium atom in the stable hexacarbonylvanadate(-I) anion, $[V(CO)_6]^-$? (Atomic number V = 23)
Answer: C
💡 Solution & Explanation
The complex is $[V(CO)_6]^-$. The oxidation state of Vanadium is $-1$. Atomic number of $V = 23$. Formula: $EAN = Z - \text{O.S.} + 2(\text{C.N.})$ $EAN = 23 - (-1) + 2(6) = 23 + 1 + 12 = 36$. The anion achieves the noble gas configuration of Krypton (36).
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