A mixture X is prepared containing mole of and mole of dissolved in of solution. If of this mixture — Coordination Compounds Chemistry Question

💡 Solution & Explanation

In $2 \text{ L}$ of solution, there are $0.02$ moles of each complex. Therefore, $1 \text{ L}$ of the mixture contains $0.01$ mole of $[Co(NH_3)_5SO_4]Br$ and $0.01$ mole of $[Co(NH_3)_5Br]SO_4$. Only the $Br^-$ ions outside the coordination sphere will precipitate with $AgNO_3$ as $AgBr$. The second complex has $SO_4^{2-}$ outside, which does not precipitate with $Ag^+$. Thus, $0.01$ moles of $AgBr$ are formed. $Y = 0.01$, making $Y \times 100 = 1$.