Which of the following diatomic species does not exist under normal conditions due to a calculated b — Chemical Bonding Chemistry Question
Question
Which of the following diatomic species does not exist under normal conditions due to a calculated bond order of zero?
Answer: D
💡 Solution & Explanation
Beryllium has an atomic number of 4, meaning $Be_2$ has 8 electrons. Its MOT configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2$. The number of bonding electrons ($N_b = 4$) equals the number of antibonding electrons ($N_a = 4$). Thus, Bond Order = $\frac{4 - 4}{2} = 0$, meaning the molecule cannot stably exist.
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