In the Born-Haber cycle for the formation of an ionic compound , the following enthalpy values (in ) — Chemical Bonding Chemistry Question
Question
In the Born-Haber cycle for the formation of an ionic compound $MX(s)$, the following enthalpy values (in $kJ/mol$) are given: $\Delta H_f = -400$, $\Delta H_{sub} (M) = 100$, $IE (M) = 500$, Bond dissociation enthalpy of $X_2 = 200$, Lattice enthalpy of $MX(s) = -800$. What is the magnitude of the electron gain enthalpy (in $kJ/mol$) for the formation of $X^-(g)$?
💡 Solution & Explanation
$\Delta H_f = \Delta H_{sub} + IE + \frac{1}{2}\Delta H_{diss} + \Delta H_{eg} + \Delta H_{lattice}$. Substituting values: $-400 = 100 + 500 + \frac{1}{2}(200) + \Delta H_{eg} - 800$. $\Delta H_{eg} = -400 - 100 - 500 - 100 + 800 = -300 \text{ kJ/mol}$. The magnitude is $300$.