Based on quantum mechanical formulations, what is the exact orbital angular momentum of an electron — Atomic Structure Chemistry Question

💡 Solution & Explanation

The magnitude of orbital angular momentum is determined solely by the azimuthal quantum number $l$ and is given by the formula $L = \sqrt{l(l+1)} \frac{h}{2\pi}$. For any $s$ -orbital (including $2s$), $l = 0$. Substituting $l = 0$ into the formula yields an orbital angular momentum of exactly zero.