Which specific atomic orbital is characterized by having exactly angular nodes and a total of nodes? — Atomic Structure Chemistry Question

💡 Solution & Explanation

The number of angular nodes is given by the azimuthal quantum number $l$. Since it has $3$ angular nodes, $l=3$, which corresponds to an $f$ orbital. The total number of nodes is $(n-1)$. Since $(n-1) = 3$, the principal quantum number $n=4$. Therefore, the orbital is $4f$.