Aldehydes Ketones and Carboxylic AcidshardNUMERICAL

The dry distillation of the calcium salt of Adipic acid (Hexanedioic acid) forces an intramolecular Aldehydes Ketones and Carboxylic Acids Chemistry Question

Question

The dry distillation of the calcium salt of Adipic acid (Hexanedioic acid) forces an intramolecular ring closure, yielding a cyclic ketone and eliminating calcium carbonate. How many carbon atoms constitute the main ring of the resulting cyclic ketone?

Answer: 5

💡 Solution & Explanation

Adipic acid ($HOOC-(CH_2)_4-COOH$) is a 6-carbon dicarboxylic acid. When its calcium salt undergoes dry distillation, one carbon is lost as part of the $CaCO_3$ leaving group. The remaining 5 carbons form a stable 5-membered cyclic ketone known as Cyclopentanone.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full IChO (Chemistry Olympiad) content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry