An organic chemist compares the reaction rates of three different aromatic hydrocarbons—toluene, eth — Haloalkanes and Haloarenes Chemistry Question
Question
An organic chemist compares the reaction rates of three different aromatic hydrocarbons—toluene, ethylbenzene, and cumene (isopropylbenzene)—with NBS under UV irradiation. Which compound reacts the fastest, and what is the determining fundamental factor?
💡 Solution & Explanation
The rate-determining step in NBS bromination is the abstraction of the benzylic hydrogen atom by a bromine radical. The activation energy for this step directly correlates with the stability of the resulting intermediate radical (Bell-Evans-Polanyi principle). Toluene forms a $1^\circ$ benzylic radical; ethylbenzene forms a $2^\circ$ benzylic radical; cumene forms a $3^\circ$ benzylic radical. Hyperconjugation from adjacent alkyl groups further stabilizes the radical. Therefore, the $3^\circ$ benzylic radical formed from cumene is the most stable, resulting in the lowest activation energy and the fastest reaction rate.