of acetic acid is shaken with of activated carbon. The final concentration of the solution after ads — Surface Chemistry Chemistry Question

💡 Solution & Explanation

Initial moles of acetic acid $= 0.6\text{ M} \times 0.1\text{ L} = 0.06\text{ mol}$. Final moles $= 0.5\text{ M} \times 0.1\text{ L} = 0.05\text{ mol}$. Moles adsorbed $= 0.06 - 0.05 = 0.01\text{ mol}$. Mass of acetic acid adsorbed $= 0.01\text{ mol} \times 60\text{ g mol}^{-1} = 0.6\text{ g} = 600\text{ mg}$. Mass adsorbed per gram of carbon $= 600\text{ mg} / 2\text{ g} = 300\text{ mg}$.