of oxygen gas is adsorbed on of metal powder. What is the volume of oxygen adsorbed per gram of the β Surface Chemistry Chemistry Question
Question
$3.6\text{ g}$ of oxygen gas is adsorbed on $1.2\text{ g}$ of metal powder. What is the volume of oxygen adsorbed per gram of the adsorbent at S.T.P. (in Liters)? Assume $1\text{ mole}$ of an ideal gas occupies $22.4\text{ L}$ at S.T.P.
Answer: 2.1
π‘ Solution & Explanation
Mass of $O_2$ adsorbed per gram of adsorbent $= 3.6 / 1.2 = 3.0\text{ g}$. Number of moles of $O_2$ per gram $= 3.0 / 32\text{ mol}$. Volume of $O_2$ at S.T.P. $= (3.0 / 32) \times 22.4\text{ L} = 2.1\text{ L}$.
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