For a gas strictly obeying the van der Waals equation, its Boyle temperature () is times its critica — States of Matter and Gaseous State Chemistry Question
Question
For a gas strictly obeying the van der Waals equation, its Boyle temperature ($T_B$) is $x$ times its critical temperature ($T_c$). Calculate the exact integer value of $8x$.
Answer: 27
💡 Solution & Explanation
The Boyle temperature $T_B = a/Rb$. The critical temperature $T_c = 8a/27Rb$. The ratio $x = T_B / T_c = (a/Rb) / (8a/27Rb) = 27/8$. Since $x = 27/8$, multiplying by 8 gives $8x = 27$.
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