An ideal gas molecule is present at . By exactly how many degrees Celsius must its temperature be ra — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

Initial temperature $T_1 = 27^\circ\text{C} = 300\text{ K}$. All molecular speeds are proportional to $\sqrt{T}$. For the speeds to double, the new temperature $T_2$ must be $4$ times the original temperature. Thus, $T_2 = 4 \times 300\text{ K} = 1200\text{ K}$. The required raise in temperature is $\Delta T = 1200\text{ K} - 300\text{ K} = 900\text{ K}$. A change of $900\text{ K}$ is exactly equivalent to a change of $900^\circ\text{C}$.