Exactly of hydrogen gas () effuses through a fine aperture in . What is the exact time (in ) require — States of Matter and Gaseous State Chemistry Question
Question
Exactly $1.0\text{ Litre}$ of hydrogen gas ($H_2$) effuses through a fine aperture in $8\text{ minutes}$. What is the exact time (in $\text{minutes}$) required for $1.0\text{ Litre}$ of ozone gas ($O_3$) to effuse through the same aperture under identical conditions?
Answer: 39.2
💡 Solution & Explanation
From Graham's Law, for equal volumes, $t_2 / t_1 = \sqrt{M_2 / M_1}$. Molar mass of $O_3 = 48\text{ g/mol}$, $H_2 = 2\text{ g/mol}$. $t_{O_3} / 8\text{ min} = \sqrt{48 / 2} = \sqrt{24}$. Since $\sqrt{24} \approx 4.899$, $t_{O_3} = 8 \times 4.899 = 39.192\text{ min}$. To one decimal, it is $39.2$.
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