The average kinetic energy of a single molecule of an ideal monoatomic gas at in SI units is approxi — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

The average kinetic energy per molecule is given by $(3/2)kT$, where $k$ is the Boltzmann constant ($1.38 \times 10^{-23}\text{ J/K}$) and $T$ is absolute temperature ($300\text{ K}$). $KE = (3/2) \times 1.38 \times 10^{-23} \times 300 = 6.21 \times 10^{-21}\text{ J}$.