The density of an ideal gas is found to be at and pressure. What will be its density (in ) at STP co — States of Matter and Gaseous State Chemistry Question
Question
The density of an ideal gas is found to be $5.46\text{ g dm}^{-3}$ at $27^\circ\text{C}$ and $2\text{ bar}$ pressure. What will be its density (in $\text{g dm}^{-3}$) at STP conditions ($0^\circ\text{C}$ and $1\text{ bar}$)? (Round off to the nearest integer).
💡 Solution & Explanation
From $PM = dRT$, we know $d = PM/RT$. For the same gas, $M$ is constant, so $d_1 T_1 / P_1 = d_2 T_2 / P_2$. Let state 1 be $27^\circ\text{C}$ ($300\text{ K}$), $2\text{ bar}$ and state 2 be $0^\circ\text{C}$ ($273\text{ K}$), $1\text{ bar}$. $d_2 = d_1 \times (P_2/P_1) \times (T_1/T_2) = 5.46 \times (1/2) \times (300/273) = 2.73 \times (300/273) = 3\text{ g dm}^{-3}$.