States of Matter and Gaseous StatehardNUMERICAL

An air bubble starts rising from the bottom of a lake. Its diameter is at the bottom and at the surfStates of Matter and Gaseous State Chemistry Question

Question

An air bubble starts rising from the bottom of a lake. Its diameter is $3.6\text{ mm}$ at the bottom and $14.4\text{ mm}$ at the surface. Assuming the temperature of the lake is uniformly constant and the atmospheric pressure at the surface is equivalent to $10\text{ m}$ of water column, what is the exact depth of the lake (in $\text{m}$)?

Answer: 630

💡 Solution & Explanation

Since $V \propto d^3$, the volume ratio $V_{surface}/V_{bottom} = (14.4/3.6)^3 = 4^3 = 64$. By Boyle's Law, $P_{bottom}V_{bottom} = P_{surface}V_{surface} \implies P_{bottom} = P_{surface} \times 64 = 10\text{ m} \times 64 = 640\text{ m}$. Depth $h = P_{bottom} - P_{surface} = 640 - 10 = 630\text{ m}$.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry