If the solubility of a specific gas 'X' is measured to be exactly at a partial pressure of , what wi — Solutions and Colligative Properties Chemistry Question
Question
If the solubility of a specific gas 'X' is measured to be exactly $0.5\text{ g L}^{-1}$ at a partial pressure of $1\text{ bar}$, what will be its theoretical solubility (in $\text{g L}^{-1}$) at an elevated pressure of $3\text{ bar}$, assuming constant temperature and strict adherence to Henry's law?
Answer: 1.5
💡 Solution & Explanation
According to Henry's law, the mass of gas dissolved per unit volume of solvent ($m$) is directly proportional to its partial pressure ($p$). Therefore, $\frac{m_1}{p_1} = \frac{m_2}{p_2} \implies \frac{0.5}{1} = \frac{m_2}{3} \implies m_2 = 1.5\text{ g L}^{-1}$.
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