A pharmaceutical formulation requires dissolving of aspirin in exactly of water. What is the mass pe — Solutions and Colligative Properties Chemistry Question
Question
A pharmaceutical formulation requires dissolving $3.65\text{ g}$ of aspirin in exactly $25.08\text{ g}$ of water. What is the mass percent ($\%\, w/w$) of aspirin in the final mixture? (Provide your answer rounded to one decimal place, e.g., if you find 15.65, write 15.7)
Answer: 12.7
💡 Solution & Explanation
Mass of solute (aspirin) = $3.65\text{ g}$. Mass of solvent (water) = $25.08\text{ g}$. Total mass of solution = $3.65 + 25.08 = 28.73\text{ g}$. The mass percent ($\%\, w/w$) is $\frac{\text{Mass of solute}}{\text{Total mass}} \times 100 = \frac{3.65}{28.73} \times 100 = 12.704\%$. Rounded to one decimal place, it is $12.7$.
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