Calculate the precise mass (in milligrams) of pure present in of a aqueous solution. (Molar mass of — Solutions and Colligative Properties Chemistry Question

💡 Solution & Explanation

For $H_2SO_4$, the n-factor is 2, so the Equivalent mass $E = \frac{98}{2} = 49\text{ g/eq}$. The formula for mass is $W = N \times E \times V(\text{in L})$. Substituting the values: $W = \frac{1}{7} \times 49 \times \left(\frac{150}{1000}\right) = 7 \times 0.15 = 1.05\text{ grams}$. Converting to milligrams: $1.05\text{ g} = 1050\text{ mg}$.