In a Zinc Blende () unit cell, if the lattice is established by ions in a cubic close-packed (ccp) a — Solid State Chemistry Question

💡 Solution & Explanation

In the Zinc Blende structure, the $S^{2-}$ ions form the ccp/fcc lattice, contributing 4 ions per unit cell. The $Zn^{2+}$ ions occupy half of the 8 available tetrahedral voids. Therefore, the total number of $Zn^{2+}$ ions per unit cell is $\frac{1}{2} \times 8 = 4$.