Solid StatehardNUMERICAL

The ionic radii of , , and are , , and respectively. What is the coordination number of the cation iSolid State Chemistry Question

Question

The ionic radii of $Na^+$, $K^+$, and $Br^-$ are $102\text{ pm}$, $138\text{ pm}$, and $195\text{ pm}$ respectively. What is the coordination number of the $K^+$ cation in the $KBr$ crystal structure?

Answer: 6

💡 Solution & Explanation

The radius ratio for $KBr$ is $\frac{r_{K^+}}{r_{Br^-}} = \frac{138}{195} \approx 0.707$. Because this ratio falls within the $0.414$ to $0.732$ limiting range, the $K^+$ ion fits into an octahedral void, resulting in a coordination number of 6.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry