The radius of a calcium ion () is and that of an oxide ion () is . Based on these values, the predic β Solid State Chemistry Question
Question
The radius of a calcium ion ($Ca^{2+}$) is $94\text{ pm}$ and that of an oxide ion ($O^{2-}$) is $146\text{ pm}$. Based on these values, the predicted crystal structure geometry of calcium oxide ($CaO$) will be:
Answer: B
π‘ Solution & Explanation
Radius ratio $\frac{r_{Ca^{2+}}}{r_{O^{2-}}} = \frac{94}{146} \approx 0.644$. Because this value lies in the range $0.414 \le \frac{r_+}{r_-} < 0.732$, the structure will have an octahedral arrangement with a coordination number of 6.
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