In a crystalline compound, atoms of element A form a face-centered cubic (FCC) lattice. Atoms of element B occupy all the available octahedral voids and exactly half of the available tetrahedral voids

Question

In a crystalline compound, atoms of element A form a face-centered cubic (FCC) lattice. Atoms of element B occupy all the available octahedral voids and exactly half of the available tetrahedral voids. What is the precise numerical ratio of B atoms to A atoms present in the compound?

Prashant Kotian · Accepted Answer

Correct answer: 2. A atoms form the FCC lattice, yielding an effective number of A atoms = . In FCC, there are 4 octahedral voids and 8 tetrahedral voids. B occupies all 4 OVs and half of the TVs (). Total B atoms = . The ratio of B atoms to A atoms is .

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