When exactly of pure Gypsum () are heated carefully in a kiln to , how many moles of water vapor () are evolved in the process?

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Question

When exactly $2 	ext{ moles}$ of pure Gypsum ($CaSO_4 \cdot 2H_2O$) are heated carefully in a kiln to $393	ext{ K}$, how many moles of water vapor ($H_2O$) are evolved in the process?

Prashant Kotian · Accepted Answer

Correct answer: 3. The balanced chemical equation for the formation of Plaster of Paris is: . Thus, from 2 moles of Gypsum, exactly 3 moles of water vapor are lost.

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