Beryllium carbonate () is highly unstable at room temperature. To prevent its decomposition, it must — s Block Elements Chemistry Question

💡 Solution & Explanation

Due to the very small size and high polarizing power of $Be^{2+}$, $BeCO_3$ is extremely unstable and decomposes readily into $BeO$ and $CO_2$. According to Le Chatelier's principle, storing it in an atmosphere of $CO_2$ suppresses this forward decomposition reaction.