In the stable ionic state formed by alkaline earth metals (), what is the number of electrons presen β s Block Elements Chemistry Question
Question
In the stable ionic state formed by alkaline earth metals ($M^{2+}$), what is the number of electrons present in the outermost $s$ subshell?
Answer: 0
π‘ Solution & Explanation
Alkaline earth metals have the general configuration $ns^2$. They lose these two valence electrons to form stable $M^{2+}$ ions. Therefore, 0 electrons remain in the outermost $s$ subshell.
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