Consider all possible open-chain, structural (constitutional) isomeric alkynes possessing the molecular formula . Exactly how many of these specific alkyne isomers will yield a final product exhibitin

Question

Consider all possible open-chain, structural (constitutional) isomeric alkynes possessing the molecular formula $C_5H_8$. Exactly how many of these specific alkyne isomers will yield a final product exhibiting geometric (cis-trans) isomerism when subjected to partial reduction using Lindlar's catalyst?

Prashant Kotian · Accepted Answer

Correct answer: 1. The structural isomeric alkynes of are: 1-pentyne, 2-pentyne, and 3-methyl-1-butyne. 1-pentyne reduces to 1-pentene (terminal double bond, no geometric isomers). 3-methyl-1-butyne reduces to 3-methyl-1-butene (terminal double bond, no geometric isomers). 2-pentyne reduces to cis-2-pentene, which does exhibit geometric isomerism. Thus, only 1 isomer qualifies.

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