10 g of (molar mass = 100 g/mol) is dissolved in 250 mL of 1 M . After the reaction is complete, the solution is boiled to expel . What volume (in mL) of 2 M solution would be required to exactly neut

Question

10 g of $CaCO_3$ (molar mass = 100 g/mol) is dissolved in 250 mL of 1 M $HCl$. After the reaction is complete, the solution is boiled to expel $CO_2$. What volume (in mL) of 2 M $KOH$ solution would be required to exactly neutralize the excess $HCl$ remaining in the solution?

Prashant Kotian · Accepted Answer

Correct answer: 25. Moles of mol. The n-factor for neutralizing an acid is 2. Equivalents of eq = 200 meq. Total milli-equivalents of initially present = meq. Milli-equivalents of excess remaining = meq. To neutralize this with (n-factor = 1, so N = 2N): mL.

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