150 mL of 6.00 M solution is mixed with 250 mL of 3.00 M . The resulting molarity of the solution is — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

When mixing two solutions of the same solute, $M_f = \frac{M_1V_1 + M_2V_2}{V_1 + V_2}$. $M_f = \frac{150 \times 6.00 + 250 \times 3.00}{150 + 250} = \frac{900 + 750}{400} = \frac{1650}{400} = 4.125 M$.