When a solid mixture of (Compound A) and (Compound B) is used in a double titration experiment, whic — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

A is $Na_2C_2O_4$ (n=2 for redox, n=0 for acid-base). B is $KHC_2O_4 \cdot H_2C_2O_4$ which contains two oxalate groups (n=2+2=4 for redox via $KMnO_4$) and three acidic protons (n=1+2=3 for acid-base neutralization). Both undergo oxidation, but only B undergoes neutralization.