Redox Reactions and Volumetric AnalysismediumNUMERICAL

In the thermal comproportionation reaction , what is the magnitude of the change in the oxidation nuRedox Reactions and Volumetric Analysis Chemistry Question

Question

In the thermal comproportionation reaction $NH_4NO_2 \xrightarrow{\Delta} N_2 + 2H_2O$, what is the magnitude of the change in the oxidation number of the nitrogen atom originating from the ammonium ($NH_4^+$) ion?

Answer: 3

💡 Solution & Explanation

In the $NH_4^+$ ion, nitrogen has an oxidation state of -3 (since H is +1). In the product $N_2$, nitrogen is in its elemental state, meaning its oxidation state is 0. The magnitude of the change is $ | 0 - (-3) | = 3$.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry