Let the oxidation state of the central bromine atom in tribromooctaoxide () be . What is the exact v — Redox Reactions and Volumetric Analysis Chemistry Question
Question
Let the oxidation state of the central bromine atom in tribromooctaoxide ($Br_3O_8$) be $+x$. What is the exact value of $x$?
Answer: 4
💡 Solution & Explanation
The structural formula for $Br_3O_8$ is $O_3Br-BrO_2-BrO_3$. The central bromine atom is bonded to two oxygen atoms via double bonds and two other bromine atoms. Assigning the shared electron pairs completely to oxygen (-2), the central bromine loses 4 electrons contextually, giving an actual O.S. of +4.
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