What is the mathematically calculated average oxidation state of Iron in the non-stoichiometric defe — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

In the compound $Fe_{0.95}O$, let the average oxidation state of iron be $x$. The overall charge must balance oxygen's -2. $0.95x + (-2) = 0 \Rightarrow 0.95x = 2 \Rightarrow x = 2/0.95 = 200/95 \approx 2.105$.