Reaction MechanismhardMCQ SINGLE

The elimination reaction involves the initial fast reversible formation of a carbanion intermediate,Reaction Mechanism Chemistry Question

Question

The $E1cB$ elimination reaction involves the initial fast reversible formation of a carbanion intermediate, followed by a slow rate-determining departure of the leaving group. Its energy profile diagram will feature:

Answer: B

💡 Solution & Explanation

The $E1cB$ mechanism is a two-step process. Step 1 (deprotonation) is fast, indicating a lower activation barrier (first hump). Step 2 (loss of leaving group) is the slow, rate-determining step, which corresponds to the highest activation energy barrier (highest second hump).

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry