In the systematic analysis of Group V cations (), cannot be used instead of in the presence of and b — Qualitative and Quantitative Analysis Chemistry Question
Question
In the systematic analysis of Group V cations ($Ba^{2+}, Sr^{2+}, Ca^{2+}$), $Na_2CO_3$ cannot be used instead of $(NH_4)_2CO_3$ in the presence of $NH_4Cl$ and $NH_4OH$ because:
Answer: C
💡 Solution & Explanation
$Na_2CO_3$ is a strong electrolyte and provides a very high concentration of $CO_3^{2-}$ ions. This high concentration would exceed the solubility product of $MgCO_3$ as well, causing $Mg^{2+}$ (a Group VI radical) to precipitate prematurely in Group V. $(NH_4)_2CO_3$ provides a controlled, lower $CO_3^{2-}$ concentration.
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