The electronegativity of an atom on the Pauling scale is . If its electron affinity is , what is its — Periodic Table and Periodicity Chemistry Question
Question
The electronegativity of an atom on the Pauling scale is $3.0$. If its electron affinity is $4.8 \text{ eV/atom}$, what is its first ionization energy in $\text{eV/atom}$? (Assume the standard conversion $X_M = 2.8 \times X_P$).
Answer: 12
💡 Solution & Explanation
Using the conversion, the Mulliken electronegativity is $X_M = 3.0 \times 2.8 = 8.4$. The Mulliken formula is $X_M = \frac{IE + EA}{2}$. Substituting the known values: $8.4 = \frac{IE + 4.8}{2} \Rightarrow 16.8 = IE + 4.8 \Rightarrow IE = 12.0 \text{ eV/atom}$.
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