Periodic Table and PeriodicityhardNUMERICAL

Consider the following isoelectronic species: . What is the exact number of species from this list tPeriodic Table and Periodicity Chemistry Question

Question

Consider the following isoelectronic species: $O^{2-}, F^-, Na^+, Mg^{2+}, Al^{3+}$. What is the exact number of species from this list that possess a smaller ionic radius than the $F^-$ ion?

Answer: 3

💡 Solution & Explanation

For isoelectronic species (all have 10 electrons here), size is inversely proportional to atomic number ($Z$). The order of sizes is $O^{2-} (Z=8) > F^- (Z=9) > Na^+ (Z=11) > Mg^{2+} (Z=12) > Al^{3+} (Z=13)$. The species smaller than $F^-$ are $Na^+$, $Mg^{2+}$, and $Al^{3+}$, totaling 3 species.

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