Diborane () reacts with at low temperatures to initially form a white ionic solid adduct. Which of the following correctly represents the ionic formulation of this initial adduct before it converts to

Question

Diborane ($B_2H_6$) reacts with $NH_3$ at low temperatures to initially form a white ionic solid adduct. Which of the following correctly represents the ionic formulation of this initial adduct before it converts to borazine?

Prashant Kotian · Accepted Answer

Correct answer: B. Diborane undergoes asymmetrical cleavage when treated with small amines like . It initially forms the ionic adduct . Upon further heating at higher temperatures, this adduct loses hydrogen to form borazine ().

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