Which of the following statements concerning "isodiaphers" is INCORRECT? — Nuclear Chemistry and Radioactivity Chemistry Question

💡 Solution & Explanation

Isodiaphers are defined as having the same isotopic number ($N-Z$ or $A-2Z$). When a nucleus undergoes $\alpha$ -decay, it loses 2 protons and 2 neutrons, leaving the difference ($N-Z$) unchanged. Hence, a parent and its daughter product after an $\alpha$ -decay form an isodiaphere pair. A $\beta^-$ -emission converts a neutron into a proton, strictly altering the ($N-Z$) value, so it forms an isobar, not an isodiaphere. Option B is incorrect.