If the neutron-to-proton () ratio of a radioactive nucleus is too high, placing it above the zone of β Nuclear Chemistry and Radioactivity Chemistry Question
Question
If the neutron-to-proton ($n/p$) ratio of a radioactive nucleus is too high, placing it above the zone of stability, the nucleus will most likely tend to achieve stability through the primary emission of:
Answer: B
π‘ Solution & Explanation
A nucleus positioned above the stability belt has an excess of neutrons. To lower its $n/p$ ratio and enter the stability belt, a neutron decays into a proton and an electron. The electron is emitted from the nucleus as a $\beta^-$ -particle (${}_{0}^{1}n \rightarrow {}_{1}^{1}H + {}_{-1}^{0}e$).
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