The specific density of an unknown gaseous element relative to atmospheric air is evaluated to be . — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

Relative density to a specific gas acts identically to vapour density logic. $D_{\text{relative}} = \frac{M_{\text{unknown}}}{M_{\text{air}}}$. We are given $D_{\text{relative}} = 1.17$ and $M_{\text{air}} = 29\text{ g/mol}$. $M_{\text{unknown}} = 1.17 \times 29\text{ g/mol} = 33.93\text{ g/mol}$. Rounding to the nearest integer yields $34$.