In the auto-reduction of copper during Bessemerisation, moles of Copper(I) oxide () react exactly wi — Metallurgy and Isolation of Elements Chemistry Question
Question
In the auto-reduction of copper during Bessemerisation, $x$ moles of Copper(I) oxide ($Cu_2O$) react exactly with $1$ mole of Copper(I) sulphide ($Cu_2S$) to produce $y$ moles of elemental Copper. What is the value of $(x + y)$?
Answer: 8
💡 Solution & Explanation
The balanced chemical equation for the self-reduction of copper is: $2Cu_2O + Cu_2S \xrightarrow{\Delta} 6Cu + SO_2 \uparrow$. According to the stoichiometry, $x = 2$ moles of $Cu_2O$ and $y = 6$ moles of $Cu$. Thus, $x + y = 2 + 6 = 8$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes