IUPAC and NomenclaturehardNUMERICAL

In the IUPAC priority sequence of functional groups, how many of the following groups have a HIGHER IUPAC and Nomenclature Chemistry Question

Question

In the IUPAC priority sequence of functional groups, how many of the following groups have a HIGHER priority than the alcohol ($-OH$) group? $-COOH$, $-SO_3H$, $-CONH_2$, $-CHO$, $>C=O$, $-SH$, $-NH_2$, $-C \equiv C-$

Answer: 5

💡 Solution & Explanation

The IUPAC priority sequence is $-COOH > -SO_3H > -COOR > -COX > -CONH_2 > -CN > -CHO > >C=O > -OH > -SH > -NH_2$. Therefore, $-COOH$, $-SO_3H$, $-CONH_2$, $-CHO$, and $>C=O$ (total of 5 groups) have a higher priority than $-OH$.

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