IUPAC and NomenclaturehardNUMERICAL

Let be the number of secondary () carbon atoms in methylcyclopropane and be the number of primary ()IUPAC and Nomenclature Chemistry Question

Question

Let $x$ be the number of secondary ($2^\circ$) carbon atoms in methylcyclopropane and $y$ be the number of primary ($1^\circ$) carbon atoms in neopentane. What is the value of $x+y$?

Answer: 6

💡 Solution & Explanation

Methylcyclopropane has 2 secondary carbon atoms in its 3-membered ring ($x=2$). Neopentane, $C(CH_3)_4$, has 4 primary carbon atoms forming the methyl groups ($y=4$). Sum = $2 + 4 = 6$.

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