Consider the highly symmetrical compound tartaric acid (). Which of the following analytical stateme — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

Tartaric acid is symmetrical with even $n=2$. Active isomers = $2^{n-1} = 2^{2-1} = 2^1 = 2$ (this represents the $d$ and $l$ enantiomeric pair). Meso isomers = $2^{(n/2 - 1)} = 2^{(2/2 - 1)} = 2^0 = 1$. Total isomers = $2 + 1 = 3$.