Calculate the total aggregate number of stereoisomers (active and meso) for the symmetrical compound — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

The molecule is symmetrical (terminals are identical methyls) and contains an odd number of chiral centers ($n=3$). The formula for calculating the total number of stereoisomers in a symmetrical odd system is simply $2^{n-1}$. Therefore, $2^{(3-1)} = 2^2 = 4$ total isomers.