Ionic EquilibriumhardMCQ SINGLE

The of a weak monoprotic acid is and the of a weak base is . What will be the precise pH of an aqueoIonic Equilibrium Chemistry Question

Question

The $pK_a$ of a weak monoprotic acid $HA$ is $4.80$ and the $pK_b$ of a weak base $BOH$ is $4.78$. What will be the precise pH of an aqueous solution of the corresponding salt $BA$?

Answer: C

💡 Solution & Explanation

The salt $BA$ is formed from a weak acid and a weak base. The pH of its aqueous solution is given by the formula $pH = 7 + \frac{1}{2}(pK_a - pK_b)$. Substituting the given values, $pH = 7 + \frac{1}{2}(4.80 - 4.78) = 7 + \frac{1}{2}(0.02) = 7 + 0.01 = 7.01$.

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